A force vec F = 2hat i +bhat j +hat k is applied on a particle and it undergoes displacement hat i -2hat j -hat k . If work done is zero, the value of b is:

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JEE MAIN Physics QUESTION #1001

Question 1

A force \(\vec{F} = 2\hat{i}+b\hat{j}+\hat{k}\) is applied on a particle and it undergoes displacement \(\hat{i}-2\hat{j}-\hat{k}\). If work done is zero, the value of \(b\) is:

\(\dfrac{1}{2}\)✔️
2
\(\dfrac{1}{3}\)

Correct Answer Explanation

\(W = \vec{F}\cdot\vec{d} = (2)(1)+(b)(-2)+(1)(-1) = 2-2b-1 = 1-2b = 0 \Rightarrow b = \dfrac{1}{2}\).

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