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NEET Physics QUESTION #1024
Question 1
A ball of mass 0.5 kg is dropped from 40 m, hits the ground and rises to 10 m. The impulse imparted during collision is (Take \(g = 9.8\ \text{m/s}^2\)):
  • 84 NS
  • 21 NS✔️
  • 7 NS
Correct Answer Explanation
Velocity before hitting: \(v_1 = \sqrt{2\times9.8\times40} = 28\ \text{m/s}\) (downward). Velocity after: \(v_2 = \sqrt{2\times9.8\times10} = 14\ \text{m/s}\) (upward). Impulse \(= m(v_2-(-v_1)) = 0.5\times(14+28) = 0.5\times42 = 21\ \text{NS}\).