Home › MCQs › NEET Physics › Question #1026
Back to Questions
NEET Physics QUESTION #1026
Question 1
The kinetic energies of cars A and B are 100 J and 225 J. Car A stops after 1000 m and car B stops after 1500 m. The ratio \(F_A/F_B\) is:
  • \(\dfrac{1}{3}\)
  • \(\dfrac{1}{2}\)✔️
  • \(\dfrac{3}{2}\)
  • \(\dfrac{2}{3}\)
Correct Answer Explanation
By work-energy theorem: \(F \cdot d = KE\). So \(F_A = \frac{100}{1000} = 0.1\ \text{N}\) and \(F_B = \frac{225}{1500} = 0.15\ \text{N}\). Ratio: \(\frac{F_A}{F_B} = \frac{0.1}{0.15} = \frac{2}{3}\). Wait: \(\frac{0.1}{0.15}=\frac{2}{3}\). Answer is option (4) = \(\frac{2}{3}\)... re-checking: \(\frac{100/1000}{225/1500}=\frac{0.1}{0.15}=\frac{2}{3}\). Correct option index: 3.