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TEEN Physics QUESTION #1041
Question 1
De-Broglie wavelength of an electron in \(n=2\) state of hydrogen atom is close to (Bohr radius \(= 0.052\ \text{nm}\)):
  • 1.67 nm
  • 2.67 nm
  • 0.067 nm
  • 0.67 nm✔️
Correct Answer Explanation
In Bohr model: \(2\pi r_n = n\lambda\). For \(n=2\): \(r_2 = 4r_0 = 4\times0.052 = 0.208\ \text{nm}\). \(\lambda = \frac{2\pi r_2}{2} = \pi r_2 = \pi\times0.208\times10^{-9}\approx0.653\ \text{nm}\approx0.67\ \text{nm}\).