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NEET Physics QUESTION #1044
Question 1
A pipe open at both ends has fundamental frequency \(f\). It is dipped to half its length in water. The new fundamental frequency is:
  • \(\dfrac{3f}{2}\)
  • 2f
  • \(\dfrac{f}{2}\)
  • f✔️
Correct Answer Explanation
Original open pipe of length \(L\): \(f=\frac{v}{2L}\). When dipped to half length, remaining open length \(=L/2\) acts as a closed pipe (one end closed by water). Fundamental of closed pipe: \(f'=\frac{v}{4(L/2)}=\frac{v}{2L}=f\). The frequency remains \(f\).