Home › MCQs › NEET Physics › Question #1055
Back to Questions
NEET Physics QUESTION #1055
Question 1
A wire of resistance \(R\) is cut into 8 equal pieces. Four pieces in parallel form one equivalent resistance, and two such sets in series. Net effective resistance:
  • \(\dfrac{R}{16}\)
  • \(\dfrac{R}{8}\)
  • \(\dfrac{R}{64}\)
  • \(\dfrac{R}{32}\)✔️
Correct Answer Explanation
Each piece has resistance \(R/8\). Four in parallel: \(R_p = \frac{R/8}{4} = \frac{R}{32}\). Two such sets in series: \(R_{total} = 2\times\frac{R}{32} = \frac{R}{16}\). Wait: \(\frac{R/8}{4}=\frac{R}{32}\), then \(2\times\frac{R}{32}=\frac{R}{16}\). So answer is \(R/16\) = option (1). Re-check: each piece \(=R/8\), 4 in parallel \(=\frac{R/8}{4}=\frac{R}{32}\), 2 in series \(=\frac{2R}{32}=\frac{R}{16}\). Answer: option (1) = \(R/16\).