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BioTechnology
QUESTION #10568
Question 1
In a chemostat at steady state, the dilution rate $D$ equals:
Correct Answer Explanation
At chemostat steady state, washout of cells equals growth: $\dfrac{dx}{dt} = 0 = (\mu - D)x$. Since $x \neq 0$, we must have $\mathbf{\mu = D}$. The dilution rate $D = F/V$ (hโปยน) therefore directly sets the specific growth rate. This is the fundamental principle of the chemostat โ the operator controls $D$, which fixes $\mu$, which in turn fixes the steady-state substrate concentration via the Monod equation.
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