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NEET Physics QUESTION #1064
Question 1
Vernier callipers: 10 VSD = 9 MSD, least division = 0.1 cm. Zero of VS at \(x=0.1\) cm when closed (zero error = +0.1 cm). Main scale reading M = 5 cm, coinciding vernier division = 8. Measured diameter after zero error correction:
  • 4.98 cm✔️
  • 5.00 cm
  • 5.18 cm
  • 5.08 cm
Correct Answer Explanation
Least count: \(\text{LC}=1\ \text{MSD}-1\ \text{VSD}=0.1-0.09=0.01\ \text{cm}\). Reading \(= M + n\times LC = 5+8\times0.01=5.08\ \text{cm}\). Zero error \(=+0.1\ \text{cm}\) (positive). Corrected reading \(=5.08-0.10=4.98\ \text{cm}\).