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Geology QUESTION #10679
Question 1
If a fault plane has a dip angle of $35^{\circ}$, the hade of the fault plane is:
  • $45^{\circ}$
  • $55^{\circ}$✔️
  • $145^{\circ}$
  • $125^{\circ}$
Correct Answer Explanation
Hade is the angle between the fault plane and the vertical, measured in the plane of the fault. It is the complement of the dip angle: $\text{Hade} = 90^{\circ} - \text{Dip}$. With a dip of $35^{\circ}$: $\text{Hade} = 90^{\circ} - 35^{\circ} = \mathbf{55^{\circ}}$. The hade is always measured from vertical, while dip is measured from horizontal. A vertical fault has hade = $0^{\circ}$; a horizontal fault (bedding plane) has hade = $90^{\circ}$.