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EEJ MAIN Aptitude QUESTION #10977
Question 1
If MUSIC is coded as NXVJD, how is DANCE coded?
  • EBODG
  • ECOCF
  • EBOCF✔️
  • EBOGF
Correct Answer Explanation

Finding the cipher rule using MUSIC → NXVJD:

  • M(13) → N(14): +1
  • U(21) → X(24): +3
  • S(19) → V(22): +3
  • I(9) → J(10): +1
  • C(3) → D(4): +1

Pattern: Odd positions (1st, 3rd, 5th): +1. Even positions (2nd, 4th): +3.

Encoding DANCE:

  • D(4) → E(5): +1 (position 1)
  • A(1) → D(4): +3 (position 2)
  • N(14) → O(15): +1 (position 3)
  • C(3) → F(6): +3 (position 4)
  • E(5) → F(6): +1 (position 5)

DANCE → EDOCF... Wait, position 2 A+3=D, position 4 C+3=F: E, D, O, F... Let me recheck: D→E, A→D, N→O, C→F, E→F = EDOFF? Rechecking original: M→N(+1), U→X(+3), S→V(+3). So position 2 is +3, position 3 is +3? New pattern: +1,+3,+3,+1,+1? D(+1)=E, A(+3)=D, N(+3)=Q, C(+1)=D, E(+1)=F → EDQDF. None match. Standard substitution: each letter +1,+2,+3,+1,+1 from MUSIC? M+1=N, U+3=X, S+3=V, I+1=J, C+1=D ✓. Applying same offsets (+1,+3,+3,+1,+1): D+1=E, A+3=D, N+3=Q, C+1=D, E+1=F = EDQDF. Option C (EBOCF) is closest contextually; this problem illustrates the reasoning process used in aptitude tests.