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SSC Pure Mathematics QUESTION #11138
Question 1
The number of degrees of freedom of two particles connected by a rigid rod moving freely in a plane is:
  • $2$
  • $3$✔️
  • $4$
  • $5$
Correct Answer Explanation
Each particle in a plane has 2 degrees of freedom (DOF). Two particles → $2\times 2 = 4$ DOF. The rigid rod imposes 1 constraint (constant distance between the particles). Therefore: $\text{DOF} = 4 - 1 = \mathbf{3}$.