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SSC Pure Mathematics QUESTION #11165
Question 1
Domain of $f(x) = \sqrt{1-x^2}$ is:
  • $x < 1$
  • $x > 1$
  • $|x| \leq 1$✔️
  • $|x| \geq 1$
Correct Answer Explanation
For $f(x) = \sqrt{1-x^2}$ to be real-valued, we need $1-x^2 \geq 0$, i.e. $x^2 \leq 1$, which gives $-1 \leq x \leq 1$, equivalently $|x| \leq 1$.