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SSC Pure Mathematics QUESTION #11227
Question 1
The range of $\sec^{-1} x$ is:
  • $[0,\pi]$
  • $\left[0,\pi\right]\setminus\left\{\dfrac{\pi}{2}\right\}$✔️
  • $\left[-\dfrac{\pi}{2},\dfrac{\pi}{2}\right]$
  • $\left[-\dfrac{\pi}{2},\dfrac{\pi}{2}\right]\setminus\{0\}$
Correct Answer Explanation
The range of $\sec^{-1}x$ (arcsecant) is $[0,\pi]\setminus\{\pi/2\}$, since $\sec(\pi/2)$ is undefined. The domain is $|x|\geq 1$ (i.e. $x\leq -1$ or $x\geq 1$), and the range is $[0,\pi]$ excluding the point $\pi/2$ where secant is undefined.