A microcontroller running at 16,text MHz uses a prescaler of 64 on its Timer0. The timer's tick period is:

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Electronics Engineering QUESTION #11702

Question 1

A microcontroller running at $16\,\text{MHz}$ uses a prescaler of 64 on its Timer0. The timer's tick period is:

$250\,\text{ns}$
$4\,\mu\text{s}$✔️
$1\,\mu\text{s}$
$64\,\mu\text{s}$

Correct Answer Explanation

Clock period $= \dfrac{1}{16\,\text{MHz}} = 62.5\,\text{ns}$. With prescaler of 64: Timer tick $= 64 \times 62.5\,\text{ns} = \mathbf{4\,\mu\text{s}}$. This is the fundamental time resolution of the timer. An 8-bit timer would overflow every $256 \times 4\,\mu\text{s} = 1.024\,\text{ms}$.

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