A battery charger uses a transformer with a centre-tapped secondary providing pm15,text V peak to a full-wave rectifier. The average DC output voltage (ideal diodes) is approximately:

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Electronics Engineering QUESTION #11718

Question 1

A battery charger uses a transformer with a centre-tapped secondary providing $\pm15\,\text{V}$ peak to a full-wave rectifier. The average DC output voltage (ideal diodes) is approximately:

$15\,\text{V}$
$9.55\,\text{V}$✔️
$21.2\,\text{V}$
$30\,\text{V}$

Correct Answer Explanation

$V_{avg} = \dfrac{2 V_m}{\pi} = \dfrac{2 \times 15}{\pi} \approx \dfrac{30}{3.14} \approx \mathbf{9.55\,\text{V}}$. For a full-wave rectifier with peak voltage $V_m$, the average output is $2V_m/\pi$. With real diodes, subtract two diode drops: $9.55 - 1.4 \approx 8.15\,\text{V}$.

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