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CSS Statistics QUESTION #1995
Question 1
For a distribution where \(Q_1 = 40\), \(Q_2 = 60\), and \(Q_3 = 80\), Bowley's coefficient of skewness \(S_k = \dfrac{Q_3 + Q_1 - 2Q_2}{Q_3 - Q_1}\) equals:
  • 0.5
  • 1
  • −0.5
Correct Answer Explanation
Substituting: \(S_k = \dfrac{80 + 40 - 2(60)}{80 - 40} = \dfrac{120 - 120}{40} = \dfrac{0}{40} = 0\). A value of zero indicates a perfectly symmetric distribution, since the median lies exactly midway between the two quartiles.