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CSS Statistics QUESTION #1996
Question 1
The first three moments about \(a = 16\) are \(\mu_1' = -0.35\), \(\mu_2' = 2.09\), \(\mu_3' = -1.93\). The mean of the distribution is:
  • 15.65✔️
  • 16.35
  • 16
  • 15.35
Correct Answer Explanation
The mean \(\bar{x} = a + \mu_1' = 16 + (-0.35) = 15.65\). The first raw moment about any arbitrary origin \(a\) equals the deviation of the true mean from \(a\), so adding \(\mu_1'\) to \(a\) recovers the mean.