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CSS Statistics QUESTION #1997
Question 1
Using moments \(\mu_1' = -0.35\), \(\mu_2' = 2.09\) about \(a = 16\), the variance \(\mu_2\) (second central moment) of the distribution equals:
  • 2.09
  • 1.9675✔️
  • 2.2125
  • 1.7
Correct Answer Explanation
Variance \(\mu_2 = \mu_2' - (\mu_1')^2 = 2.09 - (-0.35)^2 = 2.09 - 0.1225 = 1.9675\). The central moment is obtained by subtracting the squared first raw moment from the second raw moment.