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Electrical Engineering
QUESTION #2150
Question 1
A $50\text{ kVA}$ transformer has a copper loss of $800\text{ W}$ at full load. What will be the copper loss at half load?
Correct Answer Explanation
Copper loss varies as the square of the load ($P_{cu} \propto I^2$). At half load, the loss is $(\frac{1}{2})^2 \times 800\text{ W} = \frac{1}{4} \times 800\text{ W} = 200\text{ W}$.
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