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Electrical Engineering QUESTION #2161
Question 1
Using Norton's theorem, a circuit has $I_N = 4\,\text{A}$ and $R_N = 6\,\Omega$. The maximum power deliverable to a load is:
  • $24\,\text{W}$✔️
  • $48\,\text{W}$
  • $12\,\text{W}$
  • $96\,\text{W}$
Correct Answer Explanation
Maximum power transfer requires $R_L = R_N = 6\,\Omega$. Thevenin voltage $V_{th} = I_N R_N = 24\,\text{V}$. $P_{max} = \frac{V_{th}^2}{4R_N} = \frac{576}{24} = 24\,\text{W}$.