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Electrical Engineering QUESTION #2166
Question 1
A DC-DC buck converter has $V_{in} = 24\,\text{V}$, $V_{out} = 12\,\text{V}$, $f_{sw} = 100\,\text{kHz}$, and load current $I_L = 2\,\text{A}$. The minimum inductance for continuous conduction mode (CCM) is:
  • $15\,\mu\text{H}$✔️
  • $30\,\mu\text{H}$
  • $60\,\mu\text{H}$
  • $7.5\,\mu\text{H}$
Correct Answer Explanation
Duty cycle $D = V_{out}/V_{in} = 0.5$. $L_{min} = \frac{V_{out}(1-D)}{2 f_{sw} I_L} = \frac{12 \times 0.5}{2 \times 10^5 \times 2} = \frac{6}{4 \times 10^5} = 15\,\mu\text{H}$.