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Electrical Engineering QUESTION #2175
Question 1
A single-phase transformer has $N_1 = 500$ turns and $N_2 = 100$ turns. Primary is connected to $230\,\text{V}$ AC. The secondary feeds a $10\,\Omega$ resistive load. Neglecting all losses, the primary current drawn from the source is:
  • $0.92\,\text{A}$✔️
  • $4.6\,\text{A}$
  • $46\,\text{A}$
  • $0.184\,\text{A}$
Correct Answer Explanation
$V_2 = \frac{N_2}{N_1}V_1 = \frac{100}{500}\times230 = 46\,\text{V}$. $I_2 = V_2/R = 46/10 = 4.6\,\text{A}$. By current transformation: $I_1 = I_2\times\frac{N_2}{N_1} = 4.6\times\frac{100}{500} = 0.92\,\text{A}$.