A long straight conductor carries $I = 10\,\text{A}$. The magnetic flux density $B$ at a perpendicular distance $r = 2\,\text{cm}$ from it (in free space) is:

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Electrical Engineering QUESTION #2187

Question 1

$100\,\mu\text{T}$✔️
$50\,\mu\text{T}$
$200\,\mu\text{T}$
$25\,\mu\text{T}$

Correct Answer Explanation

$B = \frac{\mu_0 I}{2\pi r} = \frac{4\pi\times10^{-7}\times10}{2\pi\times0.02} = \frac{4\times10^{-6}}{0.04\pi}\times\pi = \frac{4\times10^{-6}}{0.04} = 10^{-4}\,\text{T} = 100\,\mu\text{T}$.

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