Home › MCQs › Architecture Engineering › Question #2353
Back to Questions
Architecture Engineering QUESTION #2353
Question 1
In LRFD design of steel tension members per AISC, the design strength for the fracture limit state (net section rupture) with \(\phi_t = 0.75\) is:
  • \(\phi_t P_n = 0.90 F_y A_g\)
  • \(\phi_t P_n = 0.75 F_u A_e\)✔️
  • \(\phi_t P_n = 0.85 F_y A_g\)
  • \(\phi_t P_n = 0.75 F_y A_e\)
Correct Answer Explanation
For tension member fracture limit state: \(\phi_t P_n = 0.75 F_u A_e\) where \(F_u\) is the tensile strength, \(A_e\) is the effective net area (\(A_e = U \cdot A_n\), with \(U\) being the shear lag factor), and \(\phi_t = 0.75\). For yielding on the gross section: \(\phi_t P_n = 0.90 F_y A_g\). The governing limit state is the lesser value.