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Mechanical Engineering QUESTION #2386
Question 1
The steady-state error for a unit step input applied to a type-zero closed-loop system (with unity feedback) is:
  • \(E_s = 0\)
  • \(E_s = \frac{1}{1+K_p}\) where \(K_p = \lim_{s\to 0} Y_1(s)\)✔️
  • \(E_s = 1\)
  • \(E_s = \infty\)
Correct Answer Explanation
For a type-zero system with unit step input: \(E_s=\frac{1}{1+Y_1(0)}=\frac{1}{1+K_p}\) where \(K_p\) is the position error constant. For a type-one system (pole at origin), \(E_s=0\) for a step input.