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Mechanical Engineering QUESTION #2420
Question 1
The thermal resistance for conduction through a plane wall of thickness \(L\), area \(A\), and thermal conductivity \(k\) is:
  • \(R_{th,cond} = kA/L\)
  • \(R_{th,cond} = L/(kA)\)✔️
  • \(R_{th,cond} = L \cdot k \cdot A\)
  • \(R_{th,cond} = 1/(hA)\)
Correct Answer Explanation
By analogy with Ohm's law: \(q=\Delta T/R_{th}\). For conduction: \(R_{th,cond}=L/(kA)\) (K/W).