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Mechanical Engineering QUESTION #2446
Question 1
In free vibrations with Coulomb (dry) damping, the amplitude of successive oscillation cycles decreases by a constant amount per half-cycle of:
  • \(\Delta x = \mu m g / k = x_s\) per HALF-cycle (linear decay)✔️
  • \(\Delta x = e^{-\zeta\omega_n T}\) (exponential decay)
  • The amplitude increases due to friction
  • The amplitude decreases only when velocity is negative
Correct Answer Explanation
With Coulomb damping, the amplitude decreases LINEARLY by \(4x_s=4\mu mg/k\) per full cycle. This contrasts with viscous damping where the decay is exponential.