The total shear stress tau in a helical compression spring wire (spring index C, axial load F, wire diameter d) including the Wahl correction factor K_W is:

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Mechanical Engineering QUESTION #2463

Question 1

The total shear stress \(\tau\) in a helical compression spring wire (spring index \(C\), axial load \(F\), wire diameter \(d\)) including the Wahl correction factor \(K_W\) is:

\(\tau = \frac{8FD}{\pi d^3}\)
\(\tau = K_W \frac{8FD}{\pi d^3} = K_W \frac{8FC}{\pi d^2}\)✔️
\(\tau = \frac{16FD}{\pi d^3}\)
\(\tau = K_W \frac{4F}{\pi d^2}\)

Correct Answer Explanation

The nominal shear stress in a helical spring is \(\tau_{nom}=8FD/(\pi d^3)=8FC/(\pi d^2)\). The Wahl correction factor \(K_W=\frac{4C-1}{4C-4}+\frac{0.615}{C}\) accounts for curvature effect and direct shear.

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