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Mechanical Engineering QUESTION #2467
Question 1
The base circle diameter \(d_b\) of a gear with pitch diameter \(d\) and pressure angle \(\phi\) is:
  • \(d_b = d / \cos\phi\)
  • \(d_b = d \cdot \tan\phi\)
  • \(d_b = d \cdot \cos\phi\)✔️
  • \(d_b = d \cdot \sin\phi\)
Correct Answer Explanation
The base circle radius is related to the pitch circle radius by \(r_b = r\cos\phi\), hence \(d_b = d\cos\phi\).