In the vector loop method for position analysis of an RRR dyad with links \(L_2\) and \(L_3\), the vector closure equation projected onto the x-axis gives:

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Mechanical Engineering QUESTION #2479

Question 1

\(L_2\sin\phi_2 + L_3\sin\phi_3 = x_B - x_A\)
\(L_2\cos\phi_2 + L_3\cos\phi_3 = x_B - x_A\)✔️
\(L_2\cos\phi_2 - L_3\cos\phi_3 = x_B - x_A\)
\(L_2\phi_2 + L_3\phi_3 = x_B - x_A\)

Correct Answer Explanation

For the RRR dyad, the vector loop equation projected on x gives \(L_2\cos\phi_2 + L_3\cos\phi_3 = x_B - x_A\) and on y gives \(L_2\sin\phi_2 + L_3\sin\phi_3 = y_B - y_A\).

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