The acceleration of node B of a driver link with angular velocity \(\omega\) and angular acceleration \(\alpha=\ddot{\phi}\) has components:

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Mechanical Engineering QUESTION #2487

Question 1

\(a_{Bx} = -L_{AB}\omega^2\cos\phi + L_{AB}\alpha\sin\phi\); \(a_{By} = -L_{AB}\omega^2\sin\phi - L_{AB}\alpha\cos\phi\)
\(a_{Bx} = -L_{AB}\omega^2\cos\phi - L_{AB}\alpha\sin\phi\); \(a_{By} = -L_{AB}\omega^2\sin\phi + L_{AB}\alpha\cos\phi\)✔️
\(a_{Bx} = L_{AB}\alpha\cos\phi\); \(a_{By} = L_{AB}\alpha\sin\phi\)
\(a_{Bx} = -L_{AB}\omega^2\cos\phi\); \(a_{By} = -L_{AB}\omega^2\sin\phi\)

Correct Answer Explanation

Differentiating velocity: \(a_{Bx}=-L_{AB}\alpha\sin\phi-L_{AB}\omega^2\cos\phi\) and \(a_{By}=L_{AB}\alpha\cos\phi-L_{AB}\omega^2\sin\phi\).