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Mechanical Engineering QUESTION #2508
Question 1
The change in shear force from section A to section B of a beam equals:
  • \(V_B - V_A = M_B - M_A\)
  • \(V_B - V_A = \int_{x_A}^{x_B} q\,dx\) (area of load diagram)✔️
  • \(V_B - V_A = \frac{dM}{dx}\)
  • \(V_B - V_A = w(x_B - x_A)^2/2\)
Correct Answer Explanation
From \(dV/dx = q\) (load intensity), integrating between A and B: \(V_B - V_A = \int_{x_A}^{x_B}q\,dx\), which is the area under the load intensity diagram.