Home MCQs Mechanical Engineering Question #2519
Back to Questions
Mechanical Engineering QUESTION #2519
Question 1
In the coefficient of restitution \(e\) for direct central impact of two particles, \(e\) is defined as:
  • The ratio of relative velocity of approach to relative velocity of separation
  • \(e = \frac{v_{B2}-v_{A2}}{v_{A1}-v_{B1}}\) — ratio of relative velocity of separation to approach✔️
  • \(e = \frac{m_A v_{A1}+m_B v_{B1}}{m_A+m_B}\)
  • The ratio of kinetic energies before and after impact
Correct Answer Explanation
The coefficient of restitution: \(e=\frac{v_{B2}-v_{A2}}{v_{A1}-v_{B1}}\). For perfectly elastic impact \(e=1\); for perfectly plastic \(e=0\).