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Mechanical Engineering QUESTION #2526
Question 1
A particle moves in a straight line with constant acceleration \(a\). Starting from rest (\(v_0=0\)), the distance traveled in time \(t\) is:
  • \(s = at\)
  • \(s = \frac{1}{2}at^2\)✔️
  • \(s = \frac{at^2}{4}\)
  • \(s = 2at^2\)
Correct Answer Explanation
For constant acceleration with \(v_0=0\): integrating \(a=\text{const}\) gives \(v=at\), and integrating again gives \(s=\frac{1}{2}at^2\).