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Mechanical Engineering QUESTION #2534
Question 1
For a particle moving in polar coordinates \((r,\theta)\), the transverse component of acceleration \(a_\theta\) is:
  • \(a_\theta = \ddot{r} - r\dot{\theta}^2\)
  • \(a_\theta = r\ddot{\theta} + 2\dot{r}\dot{\theta}\)✔️
  • \(a_\theta = r\ddot{\theta} - 2\dot{r}\dot{\theta}\)
  • \(a_\theta = \ddot{\theta}/r\)
Correct Answer Explanation
In polar coordinates, acceleration components are: radial \(a_r=\ddot{r}-r\dot{\theta}^2\) and transverse \(a_\theta=r\ddot{\theta}+2\dot{r}\dot{\theta}\). The term \(2\dot{r}\dot{\theta}\) is the Coriolis acceleration component in polar form.