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CSS Pure Mathematics
QUESTION #4119
Question 1
Solve $x^2 + x > 2$ for $x \in \mathbb{R}$. What is the solution set?
Correct Answer Explanation
$x^2 + x - 2 > 0 \Rightarrow (x+2)(x-1) > 0$. Critical points $-2, 1$. Solution: $x < -2$ or $x > 1$.
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