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CSS Pure Mathematics QUESTION #4120
Question 1
Using the definition of limit, what is $\lim_{x \to 2} \frac{x^3 - 4}{x^2 + 1}$?
  • $\frac{4}{5}$✔️
  • $\frac{4}{3}$
  • $2$
  • $0$
Correct Answer Explanation
Direct substitution: $\frac{2^3 - 4}{2^2 + 1} = \frac{8-4}{4+1} = \frac{4}{5}$. The function is continuous at $x=2$.