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SSC Applied Mathematics QUESTION #4164
Question 1
Using Euler's method with $h = 0.25$ for $y' = \frac{1}{x+y}$, $y(1) = 2$, what is $y(1.25)$?
  • $2 + 0.25 \times \frac{1}{3}$✔️
  • $2 + 0.25 \times \frac{1}{1.25}$
  • $2.25$
  • $2 + \frac{1}{3}$
Correct Answer Explanation
Euler: $y_1 = y_0 + h f(x_0, y_0) = 2 + 0.25 \times \frac{1}{1+2} = 2 + \frac{0.25}{3} = 2 + \frac{1}{12} = \frac{25}{12}$.