Back to Questions
PTECH Pharmaceutics II (Industrial & Quality Control) QUESTION #5688
Question 1
In the preparation of $100 \text{ mL}$ of a $1:500$ solution of Potassium Permanganate ($KMnO_{4}$), what is the weight of the solute required?
  • $0.2 \text{ g}$✔️
  • $2.0 \text{ g}$
  • $0.5 \text{ g}$
  • $0.02 \text{ g}$
Correct Answer Explanation
Calculation: $1/500 = x/100 \Rightarrow 500x = 100 \Rightarrow x = 0.2 \text{ g}$.