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Civil Engineering QUESTION #6575
Question 1
The specific energy in open channel flow is given by:
  • \\( E = y - \\dfrac{\\alpha V^2}{2g} \\)
  • \\( E = y - \\dfrac{V^2}{2g\\alpha} \\)
  • \\( E = y + \\dfrac{V^2}{2g\\alpha} \\)
  • \\( E = y + \\dfrac{\\alpha V^2}{2g} \\)✔️
Correct Answer Explanation
Specific energy is defined as energy per unit weight measured relative to the channel bed: \(E = y + \dfrac{\alpha V^2}{2g}\), where \(y\) = flow depth, \(V\) = mean velocity, \(\alpha\) = kinetic energy correction factor, \(g\) = gravitational acceleration.