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EEJ MAIN Mathematics
QUESTION #6931
Question 1
How many integers greater than $6000$ can be formed using the digits $3, 5, 6, 7, 8$ without repeating any digit?
Correct Answer Explanation
Numbers greater than 6000 can be 4-digit or 5-digit.
5-digit numbers: All arrangements of 5 digits $= 5! = 120$.
4-digit numbers $> 6000$: The leading digit must be $6, 7,$ or $8$ (3 choices). Remaining 3 positions filled from 4 remaining digits: $3 \times 4 \times 3 \times 2 = 72$.
Total $= 120 + 72 = \mathbf{192}$
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