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EEJ MAIN Mathematics
QUESTION #6936
Question 1
Find the count of natural numbers less than $7000$ that can be formed using the digits $0, 1, 3, 7, 9$ with repetition allowed.
Correct Answer Explanation
1-digit: $1, 3, 7, 9$ (excluding 0) $= 4$
2-digit: First digit: 4 choices (1,3,7,9); second: 5 choices $= 4 \times 5 = 20$
3-digit: First digit: 4 choices; others: 5 each $= 4 \times 5 \times 5 = 100$
4-digit $< 7000$: First digit must be $1$ or $3$ (2 choices, since 7000 and above excluded — first digit can be 1, 3 only for $< 7000$; digits 7 and 9 give $\geq 7000$): $2 \times 5 \times 5 \times 5 = 250$
Total $= 4 + 20 + 100 + 250 = \mathbf{374}$
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