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EEJ MAIN Physics
QUESTION #7061
Question 1
An ideal gas occupies $2 \text{ m}^3$ at a pressure of $3 \times 10^6 \text{ Pa}$. Determine the internal energy of the gas.
Correct Answer Explanation
Assuming the gas is monoatomic (as is standard in such problems unless specified otherwise), the internal energy $U$ is given by:
$U = \frac{3}{2} nRT = \frac{3}{2} PV$
$U = \frac{3}{2} \times (3 \times 10^6 \text{ Pa}) \times (2 \text{ m}^3)$
$U = 3 \times 3 \times 10^6 = 9 \times 10^6 \text{ J}$.
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