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EEJ MAIN Physics QUESTION #7072
Question 1
Two radioactive isotopes, $A$ and $B$, have half-lives of $20$ minutes and $40$ minutes, respectively. If both samples start with an identical number of nuclei, determine the ratio of the number of decayed nuclei of $A$ to those of $B$ after a period of $80$ minutes.
  • $4:1$
  • $1:4$
  • $5:4$✔️
  • $1:16$
Correct Answer Explanation
After $80$ minutes, $A$ undergoes $4$ half-lives ($80/20$), leaving $N_A = N_0/2^4 = N_0/16$. The number of decayed nuclei for $A$ is $N_0 - N_0/16 = 15N_0/16$. $B$ undergoes $2$ half-lives ($80/40$), leaving $N_B = N_0/2^2 = N_0/4$. The number of decayed nuclei for $B$ is $N_0 - N_0/4 = 3N_0/4 = 12N_0/16$. The ratio of decayed nuclei is $15:12$, which simplifies to $5:4$.