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EEJ MAIN Physics
QUESTION #7102
Question 1
Using speed ($V$), acceleration ($A$), and force ($F$) as fundamental units, what is the dimension of Young's modulus? [cite: 476]
Correct Answer Explanation
Young's modulus has the same dimensions as pressure: $[M L^{-1} T^{-2}]$.
- $[F] = [M L T^{-2}]$
- $[V] = [L T^{-1}]$
- $[A] = [L T^{-2}]$
- By solving $Y = F^a V^b A^c$, we find $a=1, b=-4, c=2$[cite: 480].
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