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NEET Physics QUESTION #7227
Question 1

The dimensions of $(\mu_0 \varepsilon_0)^{1/2}$ are:

  • $[L^{1/2}T^{-1/2}]$
  • $[L^{-1}T]$✔️
  • $[LT^{-1}]$
  • $[L^{-1/2}T^{1/2}]$
Correct Answer Explanation

We know that $c = \dfrac{1}{\sqrt{\mu_0 \varepsilon_0}}$, where $c$ is the speed of light with dimension $[LT^{-1}]$.

Therefore: $\sqrt{\mu_0\varepsilon_0} = \dfrac{1}{c}$

$[\sqrt{\mu_0\varepsilon_0}] = [c^{-1}] = [L^{-1}T]$

So $(\mu_0\varepsilon_0)^{1/2}$ has dimensions $[L^{-1}T]$.