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NEET Physics QUESTION #7292
Question 1

The coordinates of a particle at any time $t$ are $x = 5t - 2t^2$ and $y = 10t$ (metres, seconds). The acceleration of the particle at $t = 2\text{ s}$ is:

  • $5\text{ m/s}^2$
  • $-4\text{ m/s}^2$✔️
  • $-8\text{ m/s}^2$
  • $0$
Correct Answer Explanation

$a_x = \dfrac{d^2x}{dt^2} = -4\text{ m/s}^2$ (constant)

$a_y = \dfrac{d^2y}{dt^2} = 0$

Acceleration vector $= -4\hat{i}\text{ m/s}^2$ at all times, including $t = 2\text{ s}$. Magnitude $= \mathbf{4\text{ m/s}^2}$, directed in $-x$ direction.