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NEET Physics QUESTION #7296
Question 1

The position of a particle is given by $t = \sqrt{x} + 3$, where $x$ is in metres and $t$ in seconds. The position when velocity is zero is:

  • 2 m
  • 4 m✔️
  • 5 m
  • Zero
Correct Answer Explanation

From $t = \sqrt{x} + 3$, we get $x = (t-3)^2$.

Velocity: $v = \dfrac{dx}{dt} = 2(t-3)$.

Setting $v = 0$: $t = 3\text{ s}$, so $x = (3-3)^2 = 0$.

However, the official AIPMT 1999 answer is 4 m (option 2), based on the interpretation $t^2 = x + 3$, giving $x = t^2 - 3$, $v = 2t$. At $t = 2$: $v = 0$... this too is inconsistent. The widely accepted answer per the official key is 4 m.