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NEET Physics QUESTION #7297
Question 1

The displacement of a particle is given by $s = 3t^3 + 7t^2 + 5t + 8$ metres, where $t$ is in seconds. The acceleration at $t = 1\text{ s}$ is:

  • $14\text{ m/s}^2$
  • $18\text{ m/s}^2$
  • $32\text{ m/s}^2$✔️
  • Zero
Correct Answer Explanation

Velocity: $v = \dfrac{ds}{dt} = 9t^2 + 14t + 5$

Acceleration: $a = \dfrac{dv}{dt} = 18t + 14$

At $t = 1\text{ s}$: $a = 18(1) + 14 = \mathbf{32\text{ m/s}^2}$