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NEET Physics QUESTION #7298
Question 1

A particle is thrown vertically upward. Its speed at half the maximum height is $10\text{ m/s}$. The maximum height attained is ($g = 10\text{ m/s}^2$):

  • 8 m
  • 20 m
  • 10 m✔️
  • 16 m
Correct Answer Explanation

Let maximum height $= H$. At height $H/2$, velocity $= 10\text{ m/s}$.

Using $v^2 = u^2 - 2g\cdot\dfrac{H}{2}$: $100 = u^2 - gH$

At max height: $0 = u^2 - 2gH \Rightarrow u^2 = 2gH$

Substituting: $100 = 2gH - gH = gH \Rightarrow H = \dfrac{100}{10} = \mathbf{10\text{ m}}$